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Solving Quadratic Equations by Factoring


In the previous lesson you learned to solve quadratic equations by graphing. Quadratic equations can also be solved by factoring. For example, the equation 8x2 – 4x = 0 can be solved by finding factors.

          

To solve this equation, find values of x that make the product 4x(2x – 1) equal to 0. Since the product of 0 and any number is 0, at least one of the factors in the expression must be zero.

          

The solutions of 8x2 – 4x = 0 are 0 and ½.

This method of solving quadratic equations uses the Zero Product Property.

We can use this property to solve any equation that is written in the form ab = 0.

 

Example

 

1.     Solve 3x(x – 1) = 0. Check your solution.

 

Alternative Solutions:

 

 







The solutions are 0 and 1.

 

Example

Recreation Link

 

2.   At an adventure park, you can jump off a 26-foot cliff into a pool of water below. The equation h = 16t2 + 4t + 26 describes your height h in feet t seconds after your jump. If you jump up and off the cliff, what time will you pass the height of 26 feet again?

 

Alternative Solutions:

To find the time at which this occurs, let h  26 and solve for t.

Check: Graph the equation and find the x-intercepts. We will graph the equation h = 4t(–4t + 1) on a graphing calculator.

 

The solutions are 0 and ¼. The solution 0 represents the beginning of the jump. So, you would return to your original location after a fourth of a second.

 

You will often need to factor an equation before using the Zero Product Property to solve the equation.

 

Example

 

3.     Solve x2 + 4x – 12 = 0. Check your solution.

 

Alternative Solutions:

 

 




The solutions are – 6 and 2.

 

Example

Geometry Link

 

4.   The length l of a rectangle is 2 feet more than twice its width w. The area of the rectangle is 144 square feet. Find the measures of the sides.

 

Alternative Solutions:

 

 

 











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Labels: Mathematician

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