Distance Problems - 1
If you need to find the distance between two bodies traveling at right angles away from each other, you must use the Pythagorean Theorem: a2 + b2 = c2 in addition to D = RT.
If you need to find the distance between two bodies traveling at right angles away from each other, you must use the Pythagorean Theorem: a2 + b2 = c2 in addition to D = RT.
Alfi Blog April 24, 2026 Admin Bandung IndonesiaIf you need to find the distance between two bodies traveling at right angles away from each other, you must use the Pythagorean Theorem: a2 + b2 = c2 in addition to D = RT.
Distance Problems
There are several distance problems that quadratic equations can solve. One of these types is ‘‘stream’’ problems: a vehicle travels the same distance up and back where in one direction, the ‘‘stream’s’’ average speed is added to the vehicle’s speed and in the other, the ‘‘stream’s’’ average speed is subtracted from the vehicle’s speed. Another type involves two bodies moving away from each other where their paths form a right angle (for instance, one travels north and the other west). Finally, the last type is where a vehicle makes a round trip that takes longer in one direction than in the other. In all of these types, the formula D = RT is key.
Distance Problems
There are several distance problems that quadratic equations can solve. One of these types is ‘‘stream’’ problems: a vehicle travels the same distance up and back where in one direction, the ‘‘stream’s’’ average speed is added to the vehicle’s speed and in the other, the ‘‘stream’s’’ average speed is subtracted from the vehicle’s speed. Another type involves two bodies moving away from each other where their paths form a right angle (for instance, one travels north and the other west). Finally, the last type is where a vehicle makes a round trip that takes longer in one direction than in the other. In all of these types, the formula D = RT is key.
Examples
The area of a triangle is 40 in2.
Its height is four-fifths the length of its base. What are its base and height?
The area is 40 and H = ⅘B so the formula A = ½ BH becomes 40 = ½ B(⅘B).
Alfi Blog April 22, 2026 Admin Bandung IndonesiaExamples
The area of a triangle is 40 in2.
Its height is four-fifths the length of its base. What are its base and height?
The area is 40 and H = ⅘B so the formula A = ½ BH becomes 40 = ½ B(⅘B).
Geometric
Problems
To solve word problems involving geometric shapes, write down the formula or formulas referred to in the problem. For example, after reading ‘‘The perimeter of a rectangular room . . . ’’ write P = 2L + 2W. Then fill in the information given about the formula. For example, after reading ‘‘The peri- meter of the room is 50 feet . . . ’’ write P = 50 and 50 = 2L + 2W. ‘‘Its width is two-thirds its length.’’ Write W = ⅔ L and 50 = 2L + 2W becomes 50 = 2L + 2(⅔ L).
Alfi Blog April 21, 2026 Admin Bandung IndonesiaGeometric
Problems
To solve word problems involving geometric shapes, write down the formula or formulas referred to in the problem. For example, after reading ‘‘The perimeter of a rectangular room . . . ’’ write P = 2L + 2W. Then fill in the information given about the formula. For example, after reading ‘‘The peri- meter of the room is 50 feet . . . ’’ write P = 50 and 50 = 2L + 2W. ‘‘Its width is two-thirds its length.’’ Write W = ⅔ L and 50 = 2L + 2W becomes 50 = 2L + 2(⅔ L).
Examples
An object is tossed up in the air at the rate of 40 feet per second. How long will it take for the object to hit the ground?
Alfi Blog April 20, 2026 Admin Bandung IndonesiaExamples
An object is tossed up in the air at the rate of 40 feet per second. How long will it take for the object to hit the ground?