Geometric Problems - 1
Examples
The area of a triangle is 40 in2.
Its height is four-fifths the length of its base. What are its base and height?
The area is 40 and H = ⅘B so the formula A = ½ BH becomes 40 = ½ B(⅘B).
Examples
The area of a triangle is 40 in2.
Its height is four-fifths the length of its base. What are its base and height?
The area is 40 and H = ⅘B so the formula A = ½ BH becomes 40 = ½ B(⅘B).
Alfi Blog April 22, 2026 Admin Bandung IndonesiaExamples
The area of a triangle is 40 in2.
Its height is four-fifths the length of its base. What are its base and height?
The area is 40 and H = ⅘B so the formula A = ½ BH becomes 40 = ½ B(⅘B).
Geometric
Problems
To solve word problems involving geometric shapes, write down the formula or formulas referred to in the problem. For example, after reading ‘‘The perimeter of a rectangular room . . . ’’ write P = 2L + 2W. Then fill in the information given about the formula. For example, after reading ‘‘The peri- meter of the room is 50 feet . . . ’’ write P = 50 and 50 = 2L + 2W. ‘‘Its width is two-thirds its length.’’ Write W = ⅔ L and 50 = 2L + 2W becomes 50 = 2L + 2(⅔ L).
Alfi Blog April 21, 2026 Admin Bandung IndonesiaGeometric
Problems
To solve word problems involving geometric shapes, write down the formula or formulas referred to in the problem. For example, after reading ‘‘The perimeter of a rectangular room . . . ’’ write P = 2L + 2W. Then fill in the information given about the formula. For example, after reading ‘‘The peri- meter of the room is 50 feet . . . ’’ write P = 50 and 50 = 2L + 2W. ‘‘Its width is two-thirds its length.’’ Write W = ⅔ L and 50 = 2L + 2W becomes 50 = 2L + 2(⅔ L).
Examples
An object is tossed up in the air at the rate of 40 feet per second. How long will it take for the object to hit the ground?
Alfi Blog April 20, 2026 Admin Bandung IndonesiaExamples
An object is tossed up in the air at the rate of 40 feet per second. How long will it take for the object to hit the ground?
Example
An object is dropped from the roof of a
60-foot building. How longbmust it fall to reach a height of 28 feet?
In the formula h = –16t2 + v0t + h0, h0 is 60 and v0 is zero (because the object is dropped). The object reaches a height of 28 feet when h = 28.
Alfi Blog April 19, 2026 Admin Bandung IndonesiaExample
An object is dropped from the roof of a
60-foot building. How longbmust it fall to reach a height of 28 feet?
In the formula h = –16t2 + v0t + h0, h0 is 60 and v0 is zero (because the object is dropped). The object reaches a height of 28 feet when h = 28.
The Height of a Falling Object
The height of an object dropped, thrown or fired can be computed using quadratic equations. The general formula is h = –16t2 + v0t + h0, where h is the object’s height (in feet), t is time (in seconds), h0 is the object’s initial height (that is, its height at t = 0 seconds) and v0 is the object’s initial velocity (that is, its speed at t = 0 seconds) in feet per second. If the object is tossed, thrown, or fired upward, v0 is positive. If the object is thrown downward, v0 is negative. If the object is dropped, v0 is zero. The object reaches the ground when h = 0. (The effect of air resistance is ignored.)
Alfi Blog April 18, 2026 Admin Bandung IndonesiaThe Height of a Falling Object
The height of an object dropped, thrown or fired can be computed using quadratic equations. The general formula is h = –16t2 + v0t + h0, where h is the object’s height (in feet), t is time (in seconds), h0 is the object’s initial height (that is, its height at t = 0 seconds) and v0 is the object’s initial velocity (that is, its speed at t = 0 seconds) in feet per second. If the object is tossed, thrown, or fired upward, v0 is positive. If the object is thrown downward, v0 is negative. If the object is dropped, v0 is zero. The object reaches the ground when h = 0. (The effect of air resistance is ignored.)