In the previous lesson, you learned that some divisions can be performed using factoring.
Therefore, (x2 + 4x + 3) ÷ (x +
3) = x + 1. Since the remainder is 0, the divisor is a factor of the
dividend.
You can also use algebra tiles to model the division shown
above.
You can also divide polynomials using long division. Follow
these steps to divide 2x2 + 7x + 3 by 2x + 1.
Therefore, (2x2 + 7x + 3) ÷ (2x +
1) = x + 3.
Find each quotient.
Therefore, (6y – 3) ÷ (2y
– 1) = 3.
Therefore, (x2 – 2x
– 8) ÷ (x + 2) = x – 4.
If the divisor is not a factor of the dividend, the
remainder will not be 0. The quotient can be expressed as follows.
Example
The quotient is 4y + 1 with
remainder 2.
In an expression like x2 – 4 there is no x
term. In such situations, rename the dividend using zero as the coefficient
of the missing term.
Example
If you know the area of a rectangle and the length of one
side, you can find the width by dividing polynomials.
Geometry
Link
5. Find
the width of a rectangle if its area is 10x2 + 29x +
21 square units and its length is 2x + 3 units.
Alternative
Solutions:
To
find the width, divide the area
10x2
+ 29x + 21 by the length 2x + 3.
Therefore, the width of the rectangle is 5x
+ 7 units. You can check your
answer by multiplying (2x + 3) and (5x +
7).
Sumber
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